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Bookmark or Share- Understanding Python super() with __init__() methodssuper().__init__() to make your call, which is concise and does not require you to reference the parent OR class names explicitly, which can be handy. I just want to add that for Python 2.7 or under, some people implement a name-insensitive behaviour by writing self.__class__ instead of the class name, i.e.
- How does Python's super () work with multiple inheritance?And call to super in that routine invokes init defined in First. MRO=[First, Second]. Now call to super in init defined in First will continue searching MRO and find init defined in Second, and any call to super will hit the default object init. I hope this example clarifies the concept. If you don't call super from First.
- coding style - Using "super" in C++ - Stack Overflowusing super = UserBase; // this typedef is needed only so that most derived version. // is called, which calls next super in hierarchy. // it's not needed here, just saying how to chain "super" calls if needed. // NOTE: User can't call base, base is a concept private to each class, super is not. private:
- correct way to use super (argument passing) - Stack Overflow13. As explained in Python's super () considered super, one way is to have class eat the arguments it requires, and pass the rest on. Thus, when the call-chain reaches object, all arguments have been eaten, and object.__init__ will be called without arguments (as it expects). So your code should look like this:
- java - Calling super() - Stack OverflowIn this cases you need to explicitly call super() from the constructor of your subclass, passing in whatever parameters you need to satisfy the base class's constructor. Also, the call to super() must be the first line of your inherited class's constructor. That last sentence is pretty important.
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