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I believe this is probably faster than any other way if you don't care about the lists order, if you do take care about the final order store the indexes from the original and resort by that. category_ids.sort() ones_last_index = category_ids.count('1') del category_ids[0:ones_last_index] More @Wikipedia
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- Remove all occurrences of a value from a list? - Stack OverflowI believe this is probably faster than any other way if you don't care about the lists order, if you do take care about the final order store the indexes from the original and resort by that. category_ids.sort() ones_last_index = category_ids.count('1') del category_ids[0:ones_last_index]
- Docker Desktop - An unexpected error was encountered while executing a ...things that work for me. Also solving my docker desktop issue related with WSL at the same time. Seems that current WSL from window store having issue with distribution.
- python - How do I sort a dictionary by key? - Stack OverflowNote: for Python 3.7+, see this answer Standard Python dictionaries are unordered (until Python 3.7). Even if you sorted the (key,value) pairs, you wouldn't be able to store them in a dict in a way that would preserve the ordering.
- Java Array Sort descending? - Stack OverflowIt's not directly possible to reverse sort an array of primitives (i.e., int[] arr = {1, 2, 3};) using Arrays.sort() and Collections.reverseOrder() because those methods require reference types (Integer) instead of primitive types (int).
- How to reset index in a pandas dataframe? - Stack Overflowdf.reset_index(drop=True) effectively replaces the index by the default RangeIndex. Another way to do the same thing is to straight away assign a new index using set_axis() (which I believe is what OP attempted with reindex).
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