H X | search
Click here to view H X news from 60+ newspapers.
Bookmark or Share- Find two functions f and g such that (f ∘ g)(x) = h(x ... - WyzantEssentially, to get h, we took some function (g), put in x to get g(x), and then plugged in g(x) into f to get f (g(x)). We can choose what we want for both f and g. To start off, let's simplify our equation, simply combine both -x 2 's:-x 2 + 5/3 - x 2 = -2x 2 + 5/3. To obtain h(x) there's literally so many ways we could do it. Here's one of ...
- SOLUTION: what does g(x) and f(x) mean and what purpose do they serve?The composite functions of higher math often use h(x) and g(x), in combination,,defining which comes first, and which is second. The substitution is bad enough, but using y's would make it worse.. In summary, feel free to immediately use "y =" instead of "h(x)", if it clarified the problem.
- What's h'(x)? | Wyzant Ask An Experth(x) = f 2 (x) - g 2 (x) h'(x) = [f 2 (x) - g 2 (x)]' = [f 2 (x)]' - [g 2 (x)]' We need to use the chain rule to find [f 2 (x)]' and [g 2 (x)]', that is, we need to take the derivative of (something) 2 , which is 2(something), and then multiply that by the derivative of that something.
- Consider the following function. h(x) = sin2(x) + cos(x) 0 < x < 2𝜋The derivative of the second term, cos(x), is -sin(x) So h'(x) = 2sin(x)cos(x) - sin(x) For the second question, for what values of c is h'(c) = 0: 2sin(x)cos(x) - sin(x) = 0. sin(x)[2cos(x) - 1] = 0. So either sin(x) = 0 (meaning x = π) or 2cos(x) - 1 = 0 (meaning cos(x) = 1/2, so x = π/3 or 5π/3) So c = π/3, π, and 5π/3
- Find a formula for h (x). Give an exact expression. - WyzantUsing the x values from the coordinates, we know that half a cycle spans 3.5 for a full period is 7. 7=2*pi/B B=2*pi/7. As this is a cosine function, the maximum of a cosine happens as x=0 and we know the new maximum is @ x=3 from this c=-3*2*pi/7. following the format: h(x)=a * cos(2/7*pi*x +c ) + d. we have
More
