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Bookmark or Share- How do, I write this in the form a+bi? - SocraticThe complex number is given in the trigonometric form. Its module is 2, the argument (angle) is 12π 2 = 6π. The formula transforming algebraic form to trigonometric form is: |z|eiφ = |z|(cos φ + i sin φ) In the example we have: 2ei⋅6π = 2 ⋅ (cos6π+ isin6π) = 2 ⋅ (1 +0i) = 2. Answer link. iOS. Android.
- Periodic Trends in Atomic Size - Chemistry - SocraticPeriodic trends predict differences between elemental characteristics as you move across the periodic table. Trends are based on Coulomb's law which mathematically relates several characteristics of an elements. Atomic size measured the distance between the nucleus of an atom and the outermost non-valence electrons of the atom. Atomic size decreases from left to right, because the addition of ...
- How do you find the square root of an imaginary number of the form a+bi ...The question asked what is the square root of #a+bi#. For positive Real numbers #x# , the principal square root of #x# is the positive one, which is the one we mean when we write #sqrt(x)# . This is also the square root that people commonly mean when they say "the square root of #2# " and suchlike, neglecting the fact that #2# has two square roots.
- How do you multiply #(a-bi)(a+bi)#? - Socratic(a-bi)(a+bi)-a^2+b^2 (a-bi)(a+bi) is the product of two complex conjugate numbers and their product is always real. Such numbers always have equal real part and their imaginary part are equal in magnitude, but have opposite in sign. While multiplying two complex numbers one should always remember that i^2=-1.
- How do you express (1-i)^3 in a+bi form? - SocraticMethod 1 - direct evaluation #(1-i)^3 = (1-i)(1-i)(1-i)# #color(white)((i-i)^3) = (1-2i+i^2)(1-i)# #color(white)((i-i)^3) = (-2i)(1-i)#
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