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Bookmark or Share- How would you balance: H2 + O2 --> H2O? + Example - Socratic2H_2+O_2rarr2H_2O H_2+O_2rarrH_2O Notice the imbalance of atoms. On the left side, the reactant side, there are 2 hydrogen atoms and 2 oxygen atoms. On the right side, the product side, there are 2 hydrogen atoms and only 1 oxygen atom. An important thing to remember when balancing equations is that the molecules themselves may not be changed—only their coefficients can. For example, we can ...
- What is the conjugate base of H2O? - SocraticFor the conjugate base, simply remove a proton from the parent molecule/species and CONSERVE mass and charge. If I remove H^+ from H_2O, clearly I get the hydroxide ion, OH^-. Mass and charge have been conserved. If I remove a proton from sulfuric acid, I get bisulfate anion, HSO_4^-; thus bisulfate is the conjugate base of sulfuric acid. What is the conjugate base of bisulfate ion? What is ...
- What is the VSEPR shape of the molecule H2O? - SocraticWater has tetrahedral shape, or to be more precise, bent shape. On this picture you can see tetrahedral shapes of water, ammonia and methane. But it is better to say that methane has tetrahedral shape, ammonia trigonal pyramidal and water bent.
- Why does NH3 have a lower boiling point than H2O? - SocraticWell the simplest answer is..."because God wanted in that way.." As you know, the normal boiling points of water, 100 ""^@C, and ammonia, -33.3 ""^@C..are EXCESSIVELY HIGH....especially given these are molecules of paltry molecular mass, the which gives rise to negligible dispersion force. So why so? Clearly, there is an intermolecular force operating between the water and ammonia molecules ...
- How would you balance: Na + H2O --> NaOH + H2? - Socratic2Na + 2H_2O -> 2NaOH +H_2 You have to count the number of atoms in both sides of the reaction to be equal, to make it a little easier you can make a list. So in the equation Na+H_2O->NaOH+H_2, there are 1-Na-1 2-H-3 1-O-1 So you multiply NaOH and H2O by 2, so you have 4 hydrogens in both sides, and then multiply Na by 2 to be equal to the NaOH you previously multiplied.
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