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Bookmark or Share- c - What does the %*s format specifier mean? - Stack Overflow5. The format specifier %4s outputs a String in a field width of 4—that is, printf displays the value with at least 4 character positions. If the value to be output is less than 4 character positions wide, the value is right justified in the field by default. If the value is greater than 4 character positions wide, the field width expands to ...
- How do I use %s in C correctly? - Stack OverflowUsing scanf with the %s conversion specifier will stop scanning at the first whitespace character; for example, if your input stream looks like. "This is a test". then scanf("%55s", str_buf) will read and assign "This" to str_buf. Note that the field with specifier doesn't make a difference in this case.
- c++ - .c vs .cc vs. .cpp vs .hpp vs .h vs .cxx - Stack OverflowHistorically, the first extensions used for C++ were .c and .h, exactly like for C. This caused practical problems, especially the .c which didn't allow build systems to easily differentiate C++ and C files. Unix, on which C++ has been developed, has case sensitive file systems. So some used .C for C++ files.
- What does `scanf ("%* [^\n]%*c")` mean? - Stack OverflowIt is better to use. scanf("%*[^\n]"); scanf("%*c"); to clear the stdin.This is because, in the former case (single scanf), %*[^\n] will fail when the first character to be scanned is the \n character and the rest of the format string of the scanf will be skipped which means that the %*c will not function and thus, the \n from the input will still be in the input stream.
- c - What does "%.*s" mean in printf? - Stack OverflowYou can use an asterisk (*) to pass the width specifier/precision to printf(), rather than hard coding it into the format string, i.e. printf("%.*s\n", str_len, str); It should be noted that the str_len argument must have type int (or narrower integral type, which would be promoted to int).
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